Find the probability distribution of the number of success in two tosses of a die, where a success is defined as ''getting a number greater than 4''. Also, find the mean and variance of the distribution.

Explanation

To solve the problem of finding the probability distribution of the number of successes in two tosses of a die, where a success is defined as "getting a number greater than 4", we will follow these steps:

### Step 1: Define the Sample Space
When tossing a die, the possible outcomes are {1, 2, 3, 4, 5, 6}. In two tosses, the total number of outcomes is \(6 \times 6 = 36\).

### Step 2: Define Success
A success is defined as getting a number greater than 4. The numbers greater than 4 on a die are 5 and 6. Thus, the probability of success (getting a number greater than 4) is:
- Success outcomes: {5, 6} → 2 outcomes
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