A random variable has the following probability distribution: 1 2 3 4 5 6 7 8 For the events `E=[X : X` is a prime number`],\ F={X : X<4}` , the probability `P(EuuF)` is `0. 50` b. `0. 77` c. `0. 35` d. `0. 87`

Explanation

`E={X` is a prime number `}={2,3,5,7}`



`P(E)=P(2)+P(3)+P(5)+P(7)=0.62`



`F={X<4}={X=1,2,3}`



`P(F)=P(1)+P(2)+P(3)=0.5`



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