The probability distribution of a discrete random variable `X` is given below: `X :\ 2 \ \ 3 \ \ 4 \ \ 5` `P(X):5/k \ \ 7/k \ \ 9/k \ \ 11/k` The value of `E(X)` is a. `8` b. `16` c. `32` d. `48`

Explanation

`sum p_{i}=1`


`Rightarrow frac{5}{k}+frac{7}{k}+frac{9}{k}+frac{11}{k}=1`


`Rightarrow frac{32}{k}=1`


`therefore k=32`