If the acute angle between the lines `ax^(2) + 2hxy + by^(2) = 0` is `60^(@)`, then show that `(a+3b)(3a+b) = 4h^(2)`.

If the acute angle between the lines x^(2)-4hxy+3y^(2)=0 is 60^(@) then h=

If the acute angle between the lines x^(2)-4hxy+3y^(2)=0 is 60^(@) then h=

If acute angle between lines x^(2)-2hxy+y^(2)=0 is 60^(@) then h=

If acute angle between lines ax^(2)+2hxy+by^(2)=0 is (pi)/4 , then 4h^(2)=

Show that if one of angle betwwen pair of straight lines ax^(2)+2hxy+by^(2)=0 is 60^(@) then (a+3b)(3a+b)=4h^(2)

If theta is the acute angle between the lines given by ax^(2) + 2hxy + by^(2) = 0 then prove that tan theta = |(2 sqrt (h^(2) - ab))/(a + b)| . Hence find acute angle between the lines 2x^(2) + 7xy + 3y^(2) = 0

If acute angle between lines ax^(2)+2hxy+by^(2)=0 is (pi)/6 , then a^(2)+14ab+b^(2)=

If angle between lines ax^(2)+2hxy+by^(2)=0 is (pi)/4 then 2h=

If acute angle between lines 3x^(2)-4xy+by^(2)=0 is cot^(-1)2, then b=

The lines y = mx bisects the angle between the lines ax^(2) +2hxy +by^(2) = 0 if