The correct sequence which shows decreasing order of the ionic radii of the element is

Options

A. `O^(2-) gt F^(-) gt Na^(+) gt Mg^(2+) gt A1^(3+)`
B. `A1^(3+) gt Mg^(2+) gt Na^(+) gt F^(-) gt O^(2-)`
C. `Na^(+) gt Mg^(2+) gt A1^(3+) gt O^(2-) gt F^(-)`
D. `Na^(+) gt F^(-) gt Mg^(2+) gt O^(2-) gt A1^(3+)`

Answer

A

Explanation

For isoelectronic ions , following the same reasoning as discussed as Ans .27 the correct order of decreasing ionic radii is : `O^(2-) gt F^(-) gt Na^(+) gt Mg^(2+) gt A1^(3+)` i.e., Option (a) is correct.