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The first ionisation potential of Na is ...

The first ionisation potential of `Na` is `5.1eV`. The value of electrons gain enthalpy of `Na^(+)` will be

A

`+ 2.55 eV`

B

`-2.55 eV`

C

`-5.1 eV`

D

`-10.2 eV`

Text Solution

Verified by Experts

The correct Answer is:
C
Electron gain enthalpy =- Ionizatin enthalpy
`= - 5.1 eV`
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