Which of the configuration of most electronegative elements is

Options

A. `[He] 2s^(1)`
B. `[He] 2s^(2)`
C. `[Xe] 6s^(1)`
D. `[Xe] 6s^(2)`

Explanation

To determine which electronic configuration corresponds to the most electronegative element, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Electronegativity**: Electronegativity is the tendency of an atom to attract shared electrons in a chemical bond. It generally increases across a period (from left to right) and decreases down a group (from top to bottom) in the periodic table.

2. **Identify the Elements**: From the video transcript, we have the following configurations mentioned:
- Helium (He): 1s²
- Lithium (Li): 1s² 2s¹
- Beryllium (Be): 1s² 2s²
- Sodium (Na): 1s² 2s² 2p⁶ 3s¹
- Cesium (Cs): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹
- Barium (Ba): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 4p⁶ 5s²

3. **Count Electrons and Determine Atomic Number**:
- Helium has 2 electrons (atomic number 2).
- Lithium has 3 electrons (atomic number 3).
- Beryllium has 4 electrons (atomic number 4).
- Sodium has 11 electrons (atomic number 11).
- Cesium has 55 electrons (atomic number 55).
- Barium has 56 electrons (atomic number 56).

4. **Identify the Most Electronegative Element**:
- Among the elements mentioned, electronegativity increases as we move from left to right across a period. Therefore, the most electronegative elements are typically found in the upper right corner of the periodic table.
- Fluorine (F), which has the configuration 1s² 2s² 2p⁵, is known to be the most electronegative element.

5. **Conclusion**: The electronic configuration of the most electronegative element is 1s² 2s² 2p⁵, which corresponds to Fluorine (F).

### Final Answer:
The configuration of the most electronegative element is **1s² 2s² 2p⁵** (Fluorine).

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