The questions given below contain statement -1 (Assertion ) and statement -2 (Reason ) . It has four options (a), (b) , ( c) and (d ) out of which ONLY ONE is correct . Choose the correct option as.
Statement -1. The ionic radii follows the order `: I^(-) lt I lt I^(+)`
Statement -2 . Smaller the value of `z//e` larger the size of the species .

Options

A. Statement -1 is True Statement -2 is True , Statement -2 is correct explanation for Statement -4
B. Statement -1 is True Statement -2 is True , Statement -2 is not a correct explanation for Statement -4
C. Statement -1 is True Statement -2 is False
D. Statement -1 is False Statement -2 is True

Explanation

To solve the given question, we need to analyze both statements provided in the assertion and reason.

### Step 1: Analyze Statement 1
The first statement is: "The ionic radii follows the order: I^(-) < I < I^(+)."

- **Ionic Radii Concept**: Ionic radii refer to the size of an ion. Anions (negatively charged ions) are generally larger than their neutral atoms because they gain electrons, which increases electron-electron repulsion. Conversely, cations (positively charged ions) are smaller than their neutral atoms because they lose electrons, reducing electron-electron repulsion.

- **Comparison of Iodine Species**:
- I^(-): This is an anion and will have the largest radius due to the addition of an electron.
- I: This is the neutral iodine atom and will have a radius that is smaller than I^(-) but larger than I^(+).
- I^(+): This is a cation and will have the smallest radius because it has lost an electron.

Thus, the correct order should be: I^(-) > I > I^(+). Therefore, Statement 1 is **false**.

### Step 2: Analyze Statement 2
The second statement is: "Smaller the value of z/e, larger the size of the species."

- **Understanding z/e**: Here, 'z' represents the charge of the nucleus (nuclear charge), and 'e' represents the number of electrons. The ratio z/e indicates the effective nuclear charge experienced by the electrons.

- **Relation to Ionic Size**: In general, for isoelectronic species (species with the same number of electrons), a smaller z/e ratio means that the electrons are held less tightly by the nucleus, leading to a larger ionic size. However, this statement is not universally true for all species, as it applies specifically to isoelectronic species.

Since the statement does not specify that it applies only to isoelectronic species, it is misleading in this context. Therefore, Statement 2 is also **false**.

### Conclusion
Both statements are false. Therefore, the correct option is that both statements are incorrect.

### Final Answer
The correct option is (d) Both Statement 1 and Statement 2 are false.

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