Determine the volume of `M//8 KMnO_(4)` solution required to react completely with 25.0 `cm^(3)` of `M//4 FeSO_(4)` solution in acidic medium

Explanation

To solve the problem of determining the volume of \( \frac{M}{8} \) KMnO\(_4\) solution required to react completely with 25.0 cm\(^3\) of \( \frac{M}{4} \) FeSO\(_4\) solution in acidic medium, we will follow these steps:

### Step 1: Understand the Reaction
In acidic medium, KMnO\(_4\) acts as an oxidizing agent and is reduced from MnO\(_4^-\) (Mn in +7 oxidation state) to Mn\(^{2+}\) (Mn in +2 oxidation state). The n-factor for KMnO\(_4\) in this reaction is 5 because it gains 5 electrons.

For FeSO\(_4\), iron (Fe) is oxidized from +2 oxidation state to +3 oxidation state. The n-factor for FeSO\(_4\) is 1 since it loses 1 electron.

### Step 2: Use the Formula \( n_1 V_1 = n_2 V_2 \)
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