Metallic tin in the presence of HCl is oxidized by `K_(2)Cr_(2)O_(7)` to stannic chloride, `SnCl_(4)` . What volume of deci-normal dichromate solution would be reduced by 1 g of tin.

Answer

336.9 mL

Explanation

Balanced chemical equation is
`2K_(2)Cr_(2)O_(7)+3Sn+28HCIrarr4KcI+4 CrCI_(3)+3 SnCI_(4)+14 H+_(2)O`
`2(2xx39+2xx52+7xx16)=356.1 g`
Now 356.1 Sn react with `K_(2)Cr_(2)O_(7)=(588)/(356.1)g=1.651 g`
Eq .wt of `K_(2)CrO_(7)=("mol.wt")/(6)=(294)/(6)=49`
Decinormak `K_(2)Cr_(2)O_(7)` slution means 1000 mL solution contains 4.9 g`K_(2)Cr_(2)O_(7)i.e 4.9 g K_(2)Cr_(2)O_(7)` are present in 1000 mL solution
`therefore` 1.651 g will be present in =`(1000)/(4.9)xx1.651=336.9 mL`