Can a solution of 1 M `ZnSO_(4)` be stored in a vessel made of copper ? Given that
`E_(Zn^(+2)//Zn)^(@) =-0.76V and E_(Cu^(+2)//Cu)^(@)=0.34 V`

Answer

Yes

Explanation

Since `E_(Fe^(2+),Fe)^(@)=-E_(Zn,Zn^(2+))^(@)=-0.765V` is at lower potential than `E_(Cu^(2+),Cu)^(@)=0.34V` therefore Zn can only lose electrons to `Cu^(2+)` ions conversely `Zn^(2+)` cannot accept electrons from Cu and hence the following reaction will not occur
`Zn^(2+)+Curarr +Cu^(2+)`
In other words `ZnSO_(4)` solution can be safely stored in a copper vessel