The compound in which oxygen number of oxygen is +2 is ………………..

Answer

To determine the compound in which the oxidation number of oxygen is +2, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Oxidation States**:
- The oxidation state (or oxidation number) of an element in a compound indicates the degree of oxidation (loss of electrons) of that element. Oxygen typically has an oxidation state of -2 in most compounds.

2. **Identifying Conditions for +2 Oxidation State**:
- Oxygen can exhibit a +2 oxidation state when it is bonded to a more electronegative element. The most electronegative element is fluorine (F), which has an electronegativity of 4.0.

3. **Considering the Compound OF2**:
- When oxygen is bonded to fluorine, we can consider the compound OF2 (oxygen difluoride). In this compound, the oxidation state of fluorine is -1 (since it is a halogen).

4. **Setting Up the Equation**:
- For the compound OF2, we can set up the oxidation state equation:
\[ x + 2(-1) = 0 \]
where \( x \) is the oxidation state of oxygen.

5. **Solving the Equation**:
- Rearranging the equation gives:
\[ x - 2 = 0 \implies x = +2 \]
- Therefore, the oxidation state of oxygen in OF2 is +2.

6. **Conclusion**:
- The compound in which the oxidation number of oxygen is +2 is **oxygen difluoride (OF2)**.