The largest oxidation number exhibited by an element depends on its outer eletronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number ?

Options

A. `3d^(1) 4s^(2)`
B. `3d^(3) 4s^(2)`
C. `3d^(5)4s^(1)`
D. `3d^(5)4s^(2)`

Explanation

Hishest O.N of any transition element =(n-1) d electrons + ns electrons therefore larger the number of electrons in the 3d orbitals higher is the maximum O.N
(a) `4d^(1) 4s^(2)=3 , (b) 3d^(3) 4s^(2)=3+2=5 , (c ) 3d^(5)4s^(1)=5+1=6 and (d) 3d^(5)=5+2=7`
thus option (d) is correct