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In the disproportionation reaction, 3H...

In the disproportionation reaction,
`3HCIO_(3) rarr HCIO_(4) +CI_(2)+2O_(2)+H_(2)O`
What is the equivalent mass of the oxidising agnet ?

Text Solution

Verified by Experts

`3 HCIO_(3) rarr HCIO_(4)+CI_(2)+2O_(2)+H_(2)O`
Since O.N of CI decreases from +5 inch `HCIO_(3)` to O in `CI_(2)` therefore `HCIO_(3)` acts as the oxidising agent in other words O.N decrease by 5 5 and the equivalent mass of the oxidising agent `(HCIO_(3))` i.e
`=Mol mass //5 =84.45//5 =16.89`
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