If a half cell `A+E^(-)rarrA^(-)` has a large negative potential it follows that

Options

A. a is easily reduced
B. a is readily oxidised
C. `A^(-)` is readily reduced
D. `A^(-)` is readily oxidsed

Explanation

To solve the question regarding the half-cell reaction \( A + e^- \rightarrow A^- \) having a large negative potential, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Half-Cell Reaction**: The given half-cell reaction is \( A + e^- \rightarrow A^- \). This indicates that species \( A \) is gaining an electron to form \( A^- \).

2. **Identify the Nature of the Potential**: A large negative potential suggests that the reaction is not favorable in the forward direction (reduction). This means that the species \( A \) has a low tendency to gain electrons.

3. **Relate Potential to Oxidation**: Since the half-cell has a large negative potential, it implies that \( A \) is more likely to be oxidized rather than reduced. In other words, \( A^- \) can easily lose an electron to revert back to \( A \).

4. **Conclusion**: Therefore, if the half-cell reaction has a large negative potential, it follows that \( A \) is readily oxidized. This means that the species \( A \) has a high tendency to lose electrons.

5. **Select the Correct Option**: Based on the analysis, the correct option is that \( A \) is readily oxidized.

### Final Answer:
**If a half-cell \( A + e^- \rightarrow A^- \) has a large negative potential, it follows that \( A \) is readily oxidized.**

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