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Using tha data given below is reducing p...

Using tha data given below is reducing potenial.
`E_(Cr_2O_7^(2-)//Cr^(3+))^@`=1.33 V , `E_(Cl_2//Cl^-)^@`=1.36 V
`E_(MnO_4^(-)//Mn^(2+))^@`=1.51 V , `E_(Cr^(3+) // Cr)^@` =- 0.74 V
find out which of the following is the strongest oxidising agent.

A

`CI^(-)`

B

`Mn^(2+)`

C

Cr

D

`Cr^(3+)`

Text Solution

Verified by Experts

The correct Answer is:
c
Lower the `E^(@)` stronger is the reducing agent thus Cr is the strongest reducing agent
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Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Mark the strongest reducing agent.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable oxidised species.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable ion in its reduced forms

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V In which option the order of reducing power is correct?

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