For a standard cell
`Zn(s)|Zn^(2+)(1 M)||Cu^(2+)(1 M)|Cu(s)`
Write the electrode reaction and cell reaction. Also find the e.m.f. of cell if ?
`E_(Zn^(2+)|Zn)^(@)=-0.76" V",`
`E_(Cu^(2+)|Cu)^(@)=+0.34" V"`.

Options

A. `+1.85 V`
B. `-1.85 V`
C. `+0.83 V`
D. `-0.83 V`

Answer

a

Explanation

EMF for the cell `Zn|Zn^(2+)|Cu^(2+)|Cu=0.34-(-0.76)=0.75V`
since the two cells are connected in series therefore the net EMF of the two cells
=1.10 +0.75 =1.85 V