Match the entries of column I with appropriate entires of column II Each entry in column I may have one or more than one corret option from column II if the correct matches are A-p,s, B-r,C-p,q,D-s then the correctly bubbled `4xx4` matrix should be as follows:
`{:(,"column I" ,, "column II "),((A) ,CuSO_(4)+ZnrarrCu+ZnSO_(4) , (p), "None metal displacement reaction"),((B), 2KCIO_(3)rarr2KCI+3O_(2), (q), "Disproportionation reaction "),((C ) ,3CI_(2)+6OH^(-)rarr5CI^(-)+CIO_(3)^(-)+3H_(2)O , (r),"Decompostion reaction"),((D),CI_(2)+2KIrarr2KCI+I_(2) , (s),"Redox rection" ):}`

Answer

To solve the problem of matching the entries in Column I with the appropriate entries in Column II, we need to analyze each reaction provided in Column I and determine the type of reaction it represents.

### Step-by-Step Solution:

1. **Analyzing Reaction A: CuSO₄ + Zn → Cu + ZnSO₄**
- In this reaction, zinc displaces copper from copper sulfate.
- This is a **metal displacement reaction** because a more reactive metal (zinc) displaces a less reactive metal (copper) from its compound.
- Additionally, this is also a **redox reaction** because oxidation (zinc is oxidized from 0 to +2) and reduction (copper is reduced from +2 to 0) occur simultaneously.
- **Matches**: A → (s) "Redox reaction"

2. **Analyzing Reaction B: 2KClO₃ → 2KCl + 3O₂**
- This reaction involves the decomposition of potassium chlorate into potassium chloride and oxygen.
- It is classified as a **decomposition reaction** because a single compound breaks down into multiple products.
- However, it also involves a change in oxidation states, indicating that it is a **redox reaction** (chlorine goes from +5 in KClO₃ to -1 in KCl).
- **Matches**: B → (r) "Decomposition reaction", (s) "Redox reaction"

3. **Analyzing Reaction C: 3Cl₂ + 6OH⁻ → 5Cl⁻ + ClO₃⁻ + 3H₂O**
- In this reaction, chlorine undergoes both oxidation and reduction.
- Chlorine is reduced from 0 (in Cl₂) to -1 (in Cl⁻) and also oxidized from 0 to +5 (in ClO₃⁻).
- This is a **disproportionation reaction** because one element (chlorine) is both oxidized and reduced.
- It is also a **redox reaction** due to the simultaneous oxidation and reduction.
- **Matches**: C → (q) "Disproportionation reaction", (s) "Redox reaction"

4. **Analyzing Reaction D: Cl₂ + 2KI → 2KCl + I₂**
- Here, chlorine displaces iodine in potassium iodide.
- This is a **non-metal displacement reaction** because a non-metal (chlorine) displaces another non-metal (iodine).
- Additionally, chlorine is reduced (from 0 to -1) and iodine is oxidized (-1 to 0), indicating that this is also a **redox reaction**.
- **Matches**: D → (p) "None metal displacement reaction", (s) "Redox reaction"

### Final Matches:
- A → (s)
- B → (r), (s)
- C → (q), (s)
- D → (p), (s)

### Summary of Correct Matches:
- A: s
- B: r, s
- C: q, s
- D: p, s