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" (2) "7(x-2y)^(2)-25(x-2y)+12...

" (2) "7(x-2y)^(2)-25(x-2y)+12

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Factorize : 7(x-2y)^2 - 25 (x-2y)+12

Factorise : (x-2y)^(2) - 12(x-2y) + 32

Factorize the following expressions 7(x-2y)^2-25(x-2y)-12

Factor (x + y) ^ (2) -7 (x ^ (2) -y ^ (2)) + 12 (xy) ^ (2)

Factorise: 25(x+y)^(2)- 36 (x-2y)^(2).

{:("Column" A ,, "Column" B), (225x^(2) - 625 y^(2) = ,, (a) 25(x-2) (x-2)), (x^(2) - x - y - y^(2) = ,, (b) 25(3x- 5y) (3x + 5y)), (x^(2) - x - y^(2) + y = ,, (x + y) (x - y- 1)), (25x^(2) - 100 x + 100 = ,, (d) (x - y) (x + y -1)), (,,(e) (x + y) (x + y - 1)):}

The four lines given by the equations 12 x^(2)+7 x y-12 y^(2)=0 and 12 x^(2)+7 x y-12 y^(2)-x+7 y-1=0 lie along the sides of a

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

The length of the latusretum of the parabola 169|(x-1)^(2)+(y-3)^(2)|=(5x-12y+7)^(2) , is