" (12) "y tan thetaquad (210)/(21)" ,shour thad "(1-sin theta

If tan theta=(20)/(21), show that (1-sin theta+cos theta)/(1+sin theta+cos theta)=(3)/(7)

If tan theta=20/21 , then the value of (sin theta-cos theta)/(sin theta+cos theta) is: यदि tan theta=20/21 , है, तो (sin theta-cos theta)/(sin theta+cos theta) का मान क्या है ?

If 21 tan theta=20 , then (1+sintheta+costheta):(1-sin theta+cos theta)=?

If A = [(1,-tan""(theta)/(2)),(tan""(theta)/(2), 1)] and B = [(1,tan""(theta)/(2)),(-tan""(theta)/(2), 1)] show that, AB^(-1) = [(costheta,-sin theta),(sin theta, cos theta)] .

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA (1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

Prove that: (sec theta + tan theta -1)/(tan theta - sec theta +1) = (cos theta)/(1- sin theta)

Prove that : ( sin theta- cos theta +1)/( sin theta +cos theta -1) = (1)/( sec theta - tan theta)

Prove that (sec theta-tan theta+1)/(sec theta+tan theta+1)=(1-sin theta)/(costheta) .

If a point (x, y) = (tan theta + sin theta , tan theta - sin theta ) , then the locus of (x, y) is

(tan theta+sec theta-1)(tan theta+1+sec theta)=(2sin theta)/(1-sin theta)