Calculate the half-cell potential at 298 K for the reaction,
`Zn^(2+)+2e^(-) rarr Zn`
If `[Zn^(2+)]=0.1 M` and `E^(@)=-0.76` volt.

Calculate the half cell potential at 298K for the reaction, Zn^(+2) + 2e^(-) rarr Zn " if " [Zn^(+2)] =2M, E_(Zn^(+2)//Zn)^(@) = -0.76V

If [Zn^(2+)] = 0.1 M and E^(@) = -0.76 V then half cell potential at 298 K for the reaction Zn_((aq))^(2+)+2e^(-) rarr Zn_((s)) is

Calculate E_("cell") at 25^(@)C for the reaction : Zn+Cu^(2+) (0.20M) to Zn^(2+) (0.50M)+Cu Given E^(Theta) (Zn^(2+)//Zn)= -0.76V, E^(Theta)(Cu^(2+)//Cu)=0.34V .

The measured EMF at 298 K for the cell reaction, Zn(s) + Cu^(2+)(1.0 M) rarr Cu(s) + Zn^(2+)(0.1M) is 1.13 V. Calculate E^(@) for the cell reaction.

Ag^(+) + e^(-) rarr Ag, E^(@) = + 0.8 V and Zn^(2+) + 2e rarr Zn , E^(@) = - 0.76 V Calculate the cell potential for the reaction 2Ag + Zn^(2+) rarr Zn + 2Ag^(+) ( aq)