20 g of non-electrolyte, non-volatile solute `(C_(x)H_(2x)O_(6))` when dissolved in 100 gm water at `100^(@)C`, lowers the vapour pressure of solution by `(1)/(100)`th of the vapour pressure of pure water at this temperature. What is formula of the compound ?

What is the vapour pressure of pure water at 100^(@)C temperature ?

5g of compound A was dissolved in 100g of water at 303K . The vapour pressure of the solution was found to be 4.16 kilopascal. If the vapour pressure of pure water is 4.24 kPa at this temperature, what is the molecular mass of A ?

5g of compound A was dissolved in 100g of water at 303K . The vapour pressure of the solution was found to be 4.16 kilopascal. If the vapour pressure of pure water is 4.24 kPa at this temperature, what is the molecular mass of A ?

(a) 10 g of a certain non-volatile solute were dissolved in 100 g water at 20^(@) C . The vapour pressure was lowered from 17.3555 mm to 17.2350 mm , calculate m . wt. of solute. (b) The vapour pressure of pure water at 25^(@)C is 23.62 mm . What will be the vapour pressure of a solution of 1.5 g of urea in 50 g of water?

What mass of non-volatile solute, sucrose, need to be dissolved in 100g of water to decrease the vapour pressure of water by 30%?

When 25 g of a non-volatile solute is dissolved in 100g of water, the vapour pressure is lowered by 2.25 xx 10^(-1)mm . If the vapour pressure of water at 20^(@)C is mm, what is the molecular weight of the solute?

When one mole of non-volatile solute is dissolved in three moles of solvent, the vapour pressure of the solution relative to the vapour pressure of the pure solvent is -

When 25g of a non-volatile solute is dissolved in 100g of water, the vapour pressure is lowered by 0.225 mm. If the vapour pressure of water at 25^(@)C is 17.5 mm, what is the molecular mass of solute ?