Consider `f:R->Rf(x)=3sqrt(x+sqrt(1+x^2)) + 3sqrt(x-sqrt(1+x^2))` and its inverse be given by `f^-1(x)=(x^3+ax)/b.`

If f(x)=3sqrt(1−x^2)​+3sqrt(1−x^2)​, then f(x) is

the range of f(x)=sqrt(x-1)+sqrt(3-x) is

The domain of f(x)=sqrt(x-1)+sqrt(3-x) is

f(x)=sqrt(x^(2)+1) then lim_(xto3)(f(x)-sqrt(10))/(x-3) is

If f(x) = sqrt(x + 2sqrt(2x - 4)) + sqrt(x - 2sqrt(2x - 4)) , then f'(3) = f'(6) =

If f(x) = sqrt((sqrt(x-1)-2)^2)+sqrt((sqrt(x-1)-3)^2) , then f '(2) is equal to :

If f:RtoR,f(x)=(sqrt(x^(2)+1)-3x)/(sqrt(x^(2)+1)+x) then find the range of f(x) .

If f:RtoR,f(x)=(sqrt(x^(2)+1)-3x)/(sqrt(x^(2)+1)+x) then find the range of f(x) .

The value of f(0), so that the function f(x)=(sqrt(a^2-a x+x^2)-sqrt(a^2+a x+x^2))/(sqrt(a+x)-sqrt(a-x)) becomes continuous for all x , given by a^(3/2) (b) a^(1/2) (c) -a^(1/2) (d) -a^(3/2)