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A projectile is given an initial velocit...

A projectile is given an initial velocity of ` ( hat(i) + 2 hat (j) ) m//s`, where ` hat(i)` is along the ground and `hat (j)` is along the vertical . If ` g = 10 m//s^(2) `, the equation of its trajectory is :

A

`y=x-5x^(2)`

B

`y=2x-5x^(2)`

C

`4y=2x-5x^(2)`

D

`4y=2x-25x^(2)`

Text Solution

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Knowledge Check

  • A projectile is given an initial velocity of (hat(i)+2hat(j)) The Cartesian equation of its path is (g = 10 ms^(-1)) ( Here , hati is the unit vector along horizontal and hatj is unit vector vertically upwards)

    A
    `y = 2x - 5x^2`
    B
    `y = x - 5x^2`
    C
    `4y=2x-5x^2`
    D
    `y=2x-25x^2`

  • A particle has an initial velocity of 3hat(i) + 4 hat(j) and an acceleration of 0.4 hat(i) + 0.3 hat(j) . Its speed after 10s is :

    A
    ` 7sqrt(2)` units
    B
    ` 7 units`
    C
    ` 8.5 units`
    D
    `10 units`

  • A particle has an initial velocity of 4hat(i)+4hat(j) m//s and an acceleration of -0.4 hat(i) m//s^(2) at what time will its speed be 5 m//s?

    A
    `2.5` sec
    B
    `17.5` sec
    C
    `7 sqrt(2)` sec
    D
    `8.5` sec
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