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A projectile is given an initial velocit...

A projectile is given an initial velocity of ` ( hat(i) + 2 hat (j) ) m//s`, where ` hat(i)` is along the ground and `hat (j)` is along the vertical . If ` g = 10 m//s^(2) `, the equation of its trajectory is :

A

`y=x-5x^(2)`

B

`y=2x-5x^(2)`

C

`4y=2x-5x^(2)`

D

`4y=2x-25x^(2)`

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Knowledge Check

  • A projectile is given an initial velocity of (hat(i)+2hat(j)) The Cartesian equation of its path is (g = 10 ms^(-1)) ( Here , hati is the unit vector along horizontal and hatj is unit vector vertically upwards)

    A
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