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A particle is projected with a velocity ...

A particle is projected with a velocity `v` so that its range on a horizontal plane is twice the greatest height attained. If `g` is acceleration due to gravity, then its range is

A

`(4v^(2))/(5g)`

B

`(4g)/(5v^(2))`

C

`(V^(2))/(g)`

D

`(4V^(2))/(sqrt(5g))`

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