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The position of a projectile launched fr...

The position of a projectile launched from the origin at t = 0 is given by `vacr`=`(40hati+50hatj)`mat t=2s. if the projectile was launched at an angle `theta` from the horizontal, then `theta`is (take g = 10 `ms^(–2)`

A

`"tan"^(-1)(2)/(3)`

B

`"tan"^(-1)(3)/(2)`

C

`"tan"^(-1)(7)/(4)`

D

`"tan"-1(4)/(5)`

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