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Under the action of a force, a 2 kg body...

Under the action of a force, a `2 kg` body moves such that its position x as a function of time is given by `x =(t^(3))/(3)` where x is in metre and t in second. The work done by the force in the first two seconds is .

A

`1.6 jou l e`

B

`16 jou l e`

C

`160 jou l e`

D

`1600 jou l e`

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