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A drop of liquid of density rho is float...

A drop of liquid of density `rho` is floating half-immersed in a liquid of density `d`. If `sigma` is the surface tension the diameter of the drop of the liquid is

A

`sqrt((3T)/(g(3rho-sigma)))`

B

`sqrt((6T)/(g(2rho-sigma)))`

C

`sqrt((3T)/(g(2rho-sigma)))`

D

`sqrt((3T)/(g(4rho-3sigma)))`

Text Solution

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