Home
Class 11
PHYSICS
A body of mass 0.01 kg executes simple h...

A body of mass 0.01 kg executes simple harmonic motion about x = 0 under the influence of a force as shown in figure. The time period of SHM is

A

1.05 s

B

0.52 s

C

0.25 s

D

0.03 s

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

A body of mass 0.01 kg executes simple harmonic motion (SHM) about x=0 under the influence of a force shown in the figure. The period of the SHM is

A block of mass 5 kg executes simple harmonic motion under the restoring force of a spring. The amplitude and the time period of the motion are 0.1 m and 3.14 s respectively. Fnd the maximum force exerted by the spring on the block.

A block of mass 2kg executes simple harmonic motion under the reading from at a spring .The angular and the time period of motion are 0.2 cm and 2pi sec respectively Find the maximum force execute by the spring in the block.

A body is executing simple harmonic motion under the action of a force F_(1) with time period 1 s. The time period is 2s when body is acted by another force F_(3) . What will be the total time period when both the forces are acting in same direction simultaneously ?

A particle of mass 0.50 kg executes a simple harmonic motion under a forve F = -(50 n//m)x . If crosses the centre of oscillation with a speed of 10 m//s , find the amplitude of the motion.

A particle executes simple harmonic motion under the restoring force provided by a spring. The time period is T. If the spring is divided in two equal parts and one part isused to continue the simple harmonic motion, the time period will

A particle of mass 0.50 kg executes a simple harmonic motion under a force F = – (50 N/m)x. If it crosses the centre of oscillation with a speed of 10 m/s, find the amplitude of the motion.

A body of mass 0.1 kg is executing a simple harmonic motion of amplitude 0.2 m. When the body passes through the mean position, its kinetic energy is 8xx10^(-3) J. The initial phase of oscillation is 60. What is the equation of motion of the body ?

A body executes simple harmonic motion under the action of a force F_1 with a time period (4)/(5)s . If the force is changed to F_(2) , it executes SHM with time period (3)/(5)s . If both the forces F_(1) and F_(2) act simultaneously in the same direction on the body, its time period (in seconds) is

A particle of mass 0.50 kg executes a simple harmonic motion under a force F=-(50Nm^-1)x . If it crosses the centre of oscillation with a speed of 10ms^-1 , find the amplitude of the motion.