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The surface charge density of a thin cha...

The surface charge density of a thin charged disc of radius R is `sigma`. The value of the electric field at the centre of the disc is `(sigma)/(2in_(o))`. With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc reduces by

A

`70.7% `

B

`29.3%`

C

`9.7%`

D

`14.6% `

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Knowledge Check

  • The surface charge density of a thin charged disc of radius R is sigma . The value of the electric field at the centre of the disc is (sigma)/(2epsi_0) . With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc

    A
    reduces by 70.7%
    B
    reduces by 29.3%
    C
    reduces by 9.7%
    D
    reduces by 14.6%

  • Charges q is uniformly distributed over a thin half ring of radius R . The electric field at the centre of the ring is

    A
    `(q)/(2pi^(2)epsilon_(0)R^(2))`
    B
    `(q)/(4pi^(2)epsilon_(0)R^(2))`
    C
    `(q)/(4piepsilon_(0)R^(2))`
    D
    `(q)/(2piepsilon_(0)R^(2))`

  • At which distance along the centre axis of a uniformaly charged plastic disc of radius R is the magnitude of the electric field equal to one-half the magnitude of the field at the centre of the surface of the disc ?

    A
    `(R)/(sqrt2)`
    B
    `(R)/(sqrt3)`
    C
    `sqrt2R`
    D
    `sqrt(3R)`

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