Home
Class 11
PHYSICS
In an A.C. circuit, the current flowing ...

In an A.C. circuit, the current flowing in inductance is `I = 5 sin (100 t – pi//2)` amperes and the potential difference is `V = 200 sin (100 t)` volts. The power consumption is equal to

A

`1000` watt

B

`40` watt

C

`20` watt

D

Zero

Text Solution

Verified by Experts

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

In an A.C. circuit, V and I are given by V = 100 sin ( 100t) volt. I = 100 sin ( 100 t + pi //4) mA The power dissipated in the circuit is

The equation of current in an ac circuit is I = 4 sin (100pit + pi//6) ampere. The current at the beginning (t = 0) will be –

Knowledge Check

  • In an A.C. circuit, the current flowing is I = 5 sin (100t-pi//2) ampere and the potential difference is V = 200 sin (100t) volts. The power consumption is equal to

    A
    20 W
    B
    0 W
    C
    1000 W
    D
    40 W

  • In an AC circuit, the current is given by i=5sin(100t-(pi)/2) and the AC potential is V=200sin(100) volt. Then the power consumption is

    A
    `20` watt
    B
    `40` watt
    C
    `1000` watt
    D
    `0` watt

  • In an A.C. Circuit, the current is given by I=6 sin(200 pi t+(pi)/6)A The initial value of the current is

    A
    1A
    B
    2A
    C
    3A
    D
    4A

    • Similar Questions

    Explore conceptually related problems

    In an AC circuit, the applied potential difference and the current flowing are given by V=20sin100tvolt,I=5sin(100t-pi/2) amp The power consumption is equal to

    In an AC circuit voltage applied is e=220 sin 100 t. if the impedance is 110Omega and phase difference between the current and voltage is 60^(@) the power consumption is equal to

    In an a.c. circuit, voltage and current are given by : V = 100 sin (100 t) V and I = 100 sin (100 t (pi)/3) mA respectively. The average power dissipated in one cycle is :

    In an AC circuit V and I are given by V = 100 sin 100t V and I = 100 sin (100t + pi//3) mA. The power dissipated in the circuit is

    In an AC circuit the voltage applied is E = E_(0) sin omega t . The resulting current in the circuit is I = I_(0) sin (omega t - (pi)/(2)) . The power consumption in the circuit is given by

    Home
    Profile