A pure semiconductor has equal electron and hole concentration of `10^(16) m^(-3)`. Doping by indium increases number of hole concentration `n_(h)` to `5 xx 10^(22) m^(-3)`. Then, the value of number of electron concentration `n_(e)` in the doped semiconductor is

Options

A. `10^(6)//m^(3)`
B. `10^(22)//m^(3)`
C. `2 xx 10^(6)//m^(3)`
D. `2 xx 10^(9)//m^(3)`