If `sin[pi/4.cottheta]=cos[pi/4tantheta]`, then `theta` =

If sin[(pi)/(4)cottheta] = cos[(pi)/(4)tantheta] then theta can be :

If sin[(pi)/(4)cottheta] = cos[(pi)/(4)tantheta] then theta can be :

If sin[(pi)/(4)cot theta]=cos[(pi)/(4)tan theta] then theta =

If sin[(pi)/(4)*cot theta]=cos[(pi)/(4)tan theta], then theta=

If sin((pi)/(4)cottheta)=cos((pi)/(4)tantheta), then theta is equal to

If sin((pi)/(4)costheta)=cos((pi)/(4)tantheta), then theta is equal to

If sin (picot theta)=cos (pi tantheta), then

If sin (picot theta)=cos (pi tantheta), then

I : If sin((pi)/(4)cot theta)=cos ((pi)/(4)tan theta) then theta = n pi+pi//4, n in Z II : If tan ((pi)/(2)sin theta)=cot((pi)/(2)cos theta) then sin (theta + (pi)/(4))= pm (1)/(sqrt(2))