`(sec8alpha-1)/(sec4alpha-1)=(tan8alpha)/(tan2alpha)`

(sec8 alpha-1)/(sec4 alpha-1)=(tan8 alpha)/(tan2 alpha)

Prove that, (sec 8 alpha -1)/(sec 4 alpha-1)= (tan 8 alpha)/(tan 2 alpha

If alpha_(1),alpha_(2),alpha_(3),...,alpha_(n) are in A.P whose common common difference is d then sin d[sec alpha_(1)sec alpha_(2)+sec alpha_(2)sec alpha_(3)+...+sec alpha_(n-1)sec alpha_(n)]=tan alpha_(n)-tan alpha_(1)

tan2alpha-tanalpha(1+sec2alpha)=

(1)/(sec alpha - tan alpha ) - (1)/( cos alpha)=

If sec alpha=(5)/(4), evaluate (1-tan alpha)/(1+tan alpha)

Prove the following Identity: (tan alpha+sec alpha-1)/(tan alpha-sec alpha+1)=(1+sin alpha)/(cos alpha)

If (sec^(4)alpha)/(sec^(2)beta)-(tan^(4)alpha)/(tan^(2)beta)=1 where alpha,betane(pi)/(2) , then find the value of (sec^(4)beta)/(sec^(2)alpha)-(tan^(4)beta)/(tan^(2)alpha)