The resultant amplitude due to super position of `x_(1)=sin omegat, x_(2)=5 sin (omega t +37^(@))` and `x_(3)=-15 cos omega t ` is `:`

The resultant amplitude due to superposition of three simple harmonic motions x_(1) = 3sin omega t , x_(2) = 5sin (omega t + 37^(@)) and x_(3) = - 15cos omega t is

The resultant amplitude due to superposition of three simple harmonic motions x_(1) = 3sin omega t , x_(2) = 5sin (omega t + 37^(@)) and x_(3) = - 15cos omega t is

x_(1) = 5 sin omega t x_(2) = 5 sin (omega t + 53^(@)) x_(3) = - 10 cos omega t Find amplitude of resultant SHM.

x_(1) = 5 sin omega t x_(2) = 5 sin (omega t + 53^(@)) x_(3) = - 10 cos omega t Find amplitude of resultant SHM.

x_(1) = 3 sin omega t x_(2) = 5 sin (omega t + 53^(@)) x_(3) = - 10 cos omega t Find amplitude of resultant SHM.

Find the resultant amplitude of the following simple harmonic equations : x_(1) = 5sin omega t x_(2) = 5 sin (omega t + 53^(@)) x_(3) = - 10 cos omega t

The amplitude of the vibrating particle due to superposition of two SHMs , y_(1)=sin (omega t+(pi)/(3)) and y_(2)=sin omega t is :

Find the displacement equation of the simple harmonic motion obtained by combining the motion. x_(1) = 2sin omega t , x_(2) = 4sin (omega t + (pi)/(6)) and x_(3) = 6sin (omega t + (pi)/(3))

Find the displacement equation of the simple harmonic motion obtained by combining the motion. x_(1) = 2sin omega t , x_(2) = 4sin (omega t + (pi)/(6)) and x_(3) = 6sin (omega t + (pi)/(3))