The observed wavelegnth in the line spectrum of hydrogen atom were first expressed in terms of a series by Johann Jakob Balmer, a Swiss teacher.
Balmer's emipirical formula is
`(1)/(lamda)=R_(H)[(1)/(2^(2))-(1)/(n^(2))]n=3,4,5` . . .
`R_(H)=109678cm^(-1)` is the Rydberg constant.
Niels Bohr derived this expression theoretically in 1913. The formula is generalised to any one electron atom/ion.Howmany lines in the spectrum will be observed when electrons return from 7th shell to 2nd shell?

The observed wavelengths in the line spectrum of hydrogen atom were first expressed in terms of a series by Johann Jakob Balmer, a Swiss teacher. Balmer's empirical formula is (1)/(lambda) = R_(H)[(1)/(2^(2)) - (1)/(n^(2))] = n = 3, 4,5… R_(H) = 109678 cm^(-1) is the Rydberg constant. Niels Bohr derived this expression theoretically in 1913. The formula is a generalised to any on electron atom/ion. How many lines in the spectrum will be observed when electrons returns from 7th shell to 2nd shell ?

The observed wavelegnth in the line spectrum of hydrogen atom were first expressed in terms of a series by Johann Jakob Balmer, a Swiss teacher. Balmer's emipirical formula is (1)/(lamda)=R_(H)[(1)/(2^(2))-(1)/(n^(2))]n=3,4,5 . . . R_(H)=109678cm^(-1) is the Rydberg constant. Niels Bohr derived this expression theoretically in 1913. The formula is generalised to any one electron atom/ion. The wavelength of first line of Balmer spectrum of hydrogen will be:

The observed wavelengths in the line spectrum of hydrogen atom were first expressed in terms of a series by Johann Jakob Balmer, a Swiss teacher. Balmer's empirical formula is (1)/(lambda) = R_(H)[(1)/(2^(2)) - (1)/(n^(2))] = n = 3, 4,5… R_(H) = 109678 cm^(-1) is the Rydberg constant. Niels Bohr derived this expression theoretically in 1913. The formula is a generalised to any on electron atom/ion. Which of the following is not correctly matched ?

The observed wavelengths in the line spectrum of hydrogen atom were first expressed in terms of a series by Johann Jakob Balmer, a Swiss teacher. Balmer's empirical formula is (1)/(lambda) = R_(H)[(1)/(2^(2)) - (1)/(n^(2))] = n = 3, 4,5… R_(H) = 109678 cm^(-1) is the Rydberg constant. Niels Bohr derived this expression theoretically in 1913. The formula is a generalised to any on electron atom/ion. The wavelength of first line of Balmer spectrum of hydrogen will be :

The observed wavelegnth in the line spectrum of hydrogen atom were first expressed in terms of a series by Johann Jakob Balmer, a Swiss teacher. Balmer's emipirical formula is (1)/(lamda)=R_(H)[(1)/(2^(2))-(1)/(n^(2))]n=3,4,5 . . . R_(H)=109678cm^(-1) is the Rydberg constant. Niels Bohr derived this expression theoretically in 1913. The formula is generalised to any one electron atom/ion. Q. Calculat ethe longest wavelength in Ã…(1Ã…= 10^(-10)m ) in the balmer series of singly ionized helium He^(+) . Select the correct answer. Ignore the nuclear motion in your calculation.

The observed wavelength in the line spectrum of hydrogen atom were first expressed in term of a series of johann jakob Balmer a series teacher Balmer's empirical formula is 1/lambda=R_H(I/2^2-I/N^2)"________"n ge 3 ,R_H=109678cm^-1 is Rydberg constant.Niele Bohr derived this expression theoretically in 1913 the formula is generalised to any uni electronic species. How many lines in the spectrum will be observed when an electron returns from 7th shell to 2nd shell?

The observed wavelength in the line spectrum of hydrogen atom were first expressed in term of a series of johann jakob Balmer a series teacher Balmer's empirical formula is 1/lambda=R_H(I/2^2-I/N^2) ________ n ge 3 , R_H=109678cm^-1 is Rydberg constant. Niele Bohr derived this expression theoretically in 1913 the formula is generalized to any uni-electronic species. Calculate the longest wavelength in the Balmer series of singly ionized He^+