Two lines are given by `(x-2y)^2 + k (x-2y) = 0` . The value of k, so that the distance between them is 3, is :

Two line are given (x-2y)^2+k(x-2y)=0 . The value of k, so that the distance between then is 3, is

If the lines 2x+2y+3=0 and x+y+1=0 are parallel then the distance between them is

The distance between the lines given by (x-2y)^(2)+k(x-2y)=0 is 3, then k=

If the lines given by 3x+2ky=2 and 2x+5y+1=0 are parallel,then the value of k is

.If the lines given by 2x+3ky=2 and 5x+2y+1=0 are parallel,then the value of k is

if the lines given by 3x+2ky=2 and 2x+ 5y+1=0 are parallel then the value of k is

If the lines given by 3x+2ky=2 and 2x+5y+1=0 are parallel, then the value of k is

If the lines given by 3x+ 2ky =2 and 2x+ 5y+1= 0 are parallel, then the value of k is

Find the point of intersection of the lines 4x + 3y = 1 and 3x - y + 9 = 0 . If this point lies on the line (2k - 1) x - 2y = 4 , find the value of k. The above question can also be stated as : If the lines 4x + 3y = 1, 3x – y + 9 = 0 and (2k - 1) x - 2y = 4 are concurrent (pass through the same point), find the value of k.