[" Eaction: "],[qquad [Cu(s)+2Ag^(o+)(aq),Longrightarrow Cu^(2+)(aq)+2Ag(s)],[E^(ominus)cell=0.46V," (NCERT Example 3.2) "]]

Calculate equilibrium constant for the reaction at 25^(@)C Cu(s)+2Ag^(+)(aq) hArr Cu^(2+)(aq)+2Ag(s) E^(@) value of the cell is 0.46 " V " .

The equilibrium constent of the reaction. Cu(s)+2Ag(aq). Leftrightarrow Cu^(2+) (aq.)+2Ag(s) E^(@)=0.46" V at 298 K is"

Consider the following cell reaction Cu(s)+2Ag^(+)(aq) rarr Cu^(2+) (aq) +2Ag(s) E_("cell")^(@)=0.46 V By boubling the concentration of Cu^(2+) , E_("cell") is

The equilibrium constant (K) for the reaction Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s) , will be [Given, E_(cell)^(@)=0.46 V ]

The equivalent constant of the reaction: Cu(s)+2Ag^(+)(aq.) rarr Cu^(2+)(aq.)+2Ag(s) E^(@)=0.46 V at 298 K ,is: