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A diatomic moleecule has a dipole moment...

A diatomic moleecule has a dipole moment of `1.2D`. If its bond distance is equal to `1.0 Å` then the `%` of ionic character in the diatomic molecular is `:`

A

`25%`

B

`37%`

C

`52%`

D

`42%`

Text Solution

Verified by Experts

The correct Answer is:
1
Assuming complete charge transfer then dipole moment `=(4.8xx10^(10)esu)(10^(-5)cm)=4.8D`
So, `%` ionic character `=(1.2)/(4.8)xx100%=25%`
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