For the reaction `A_(2)(g)+(1)/(8)B_(8)(g)rarrA_(2)B(g)` following data was obtained for a large concentration of `B_(8)` . What is the reaction order with respect to `A_(2)` ?
`{:("Time (min)",,[A_(2)]("moles"//L)xx10^(4)),(60,,292),(120,,198),(180,,104),(240,,010):}`

Options

A. Zero
B. One
C. Two
D. Indeterminate

Answer

1

Explanation

There is equal decrease in concentration in equal time intervals ( say 60 min each ). The reaction is
`:." "` proceeding with constant rate. Hence zero order in `A_(2)`.