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Given that E(M^(+)//M)^(@)=-0.44V and E(...

Given that `E_(M^(+)//M)^(@)=-0.44V` and `E_(X^(+)//X)^(@)=-0.33V` at `298K`. The value of `E_("cell")` for
`M(s)|M^(+)(0.1M)||X^(+)(0.2M)|X(s)` at `298K` will be `[log 2=0.3,log3=0.48,log5=0.7]`

A

`0.19V`

B

`0.127V`

C

`0.092V`

D

`0.119V`

Text Solution

Verified by Experts

The correct Answer is:
2
`E_("cell")=E_("cel")^(@)-(0.591)/(1)log.([M^(+)])/([X^(+)])`
`=[-0.33-(-0.44)]-(0.591)/(1)log.(0.1)/(0.2)`
`=0.127V " Ans."`
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