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A solution of Na(2)CO(3) is added drop b...

A solution of `Na_(2)CO_(3)` is added drop by drop to litre of a solution containing `10^(-4)` mole of `Ba^(2+)` and `10^(-5)` mole of Ag, if `K_(SP)` for `BaCO_(3)` is `8.1xx10^(-9)` and `K_(SP)` for `Ag_(2)CO_(3)is 6.9xx10^(-12)`, then which is not true ?

A

No presicpitate of `BaCO_(3)` will appear until `[CO_(3)^(2-)]` reaches `8.1xx10^(-5)` mol per litre

B

A precipitate of `Ag_(2)CO_(3)` will appear when `[CO_(3)^(2-)]` reaches `6.9xx10^(-5)` mol `"litre"^(-1)`

C

No precipitate of `Ag_(2)CO_(3)` will apppear when `[CO_(3)^(2-)]` reaches `6.9x10^(-6)`mole per litre

D

`BaCO_(3)` will be precipitated first

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Verified by Experts

The correct Answer is:
2

For precipitation of `Ag_(2)CO_(3)" "[CO_(3)^(2-)]=(K_(sp))/([Ag^(+)]^(2))=(6.9xx10^(-12))/([10^(-5)]^(2))" "=6.9xx10^(-2)`
and for precipitation of `BaCO_(3)" "[CO_(3)^(2-)]=(K_(sp))/([Ba^(2+)])=(8.1xx10^(-9))/(10^(-4))" "=8.1xx10^(-6)`
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