Addition of sodium to bromobenzene in dry ether will produce `:`

Options

A. Biphenyl
B. Benzene
C. Cyslohexane
D. No reaction

Explanation

To determine the product of the reaction between sodium and bromobenzene in dry ether, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Bromobenzene (C6H5Br)
- Sodium (Na)
- Dry ether (as the solvent)

### Step 2: Understand the Reaction Type
This reaction is known as the Wurtz reaction, which involves the coupling of alkyl or aryl halides in the presence of sodium. In this case, we are dealing with an aryl halide (bromobenzene).

### Step 3: Reaction Mechanism
1. Sodium donates an electron to the bromobenzene, leading to the formation of a phenyl radical (C6H5•) and sodium bromide (NaBr).
2. The phenyl radical can then react with another molecule of bromobenzene, leading to the formation of biphenyl (C6H5-C6H5).

### Step 4: Write the Balanced Equation
The overall reaction can be summarized as follows:
\[ 2 \text{C}_6\text{H}_5\text{Br} + 2 \text{Na} \rightarrow \text{C}_{12}\text{H}_{10} + 2 \text{NaBr} \]
Where:
- C12H10 is biphenyl.

### Step 5: Conclusion
The product formed from the addition of sodium to bromobenzene in dry ether is biphenyl.

### Final Answer
The product is biphenyl (C12H10).

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