`C_(6)H_(5)Cl+CH_(3)Cloverset(Na//"dry ether")rarrC_(6)H_(5)CH_(3)+2NaCl`
This reaction is an example of `:`

Options

A. Wurz reaction
B. Fittig reaction
C. Wurtz-Fitting reaction
D. Frankland reaction

Explanation

To solve the question regarding the reaction of chlorobenzene and methylchloromethane in the presence of sodium and dry ether, we need to identify the type of reaction taking place. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Reactants
The reactants in the given reaction are:
- Chlorobenzene (C₆H₅Cl)
- Methylchloromethane (CH₃Cl)

### Step 2: Identify the Products
The products of the reaction are:
- Methylbenzene (C₆H₅CH₃), also known as toluene
- Sodium chloride (NaCl)

### Step 3: Analyze the Reaction Conditions
The reaction occurs in the presence of sodium (Na) and dry ether. Sodium acts as a reducing agent in this reaction.

### Step 4: Mechanism of the Reaction
The reaction proceeds through a free radical mechanism. Sodium donates electrons to generate radicals:
- A phenyl radical (C₆H₅•) from chlorobenzene
- A methyl radical (CH₃•) from methylchloromethane

These radicals then combine to form methylbenzene (toluene).

### Step 5: Classify the Reaction
This reaction is classified as a Wurtz reaction. The Wurtz reaction typically involves the coupling of two alkyl halides in the presence of sodium to form a higher alkane. In this case, one of the halides is an aryl halide (chlorobenzene) and the other is an alkyl halide (methyl chloride), which fits the criteria for a Wurtz reaction.

### Final Answer
The reaction is an example of a **Wurtz reaction**.

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