An optically inactive amine `(A)` is methylated with excess of `CH_(3)I` and there after reacted with `AgOH` to form alkene `(B)`. The alkene B after ozonolysis gives `HCHO` and `CH_(3)CH_(2)CH_(2)CHO`. A and B in the reaction are respectively.

Options

A. `CH_(3)-CH_(2)-CH_(2)-NH_(2)" "&" "CH_(3)-CH_(2)-CH=CH_(2)`
B. `CH_(3)-CH_(2)-underset(underset(NH_(2))|)(C)H-CH_(2)-CH_(2)" "&" "CH_(3)-CH_(2)-CH=CH-CH_(3)`
C. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-NH_(2)" "&" "CH_(3)-CH_(2)-CH_(2)-CH=CH_(2)`
D. `CH_(3)-CH_(2)-CH_(2)-underset(underset(NH_(2))|)(C)H-CH_(3)" "&" "CH_(3)-CH_(2)-CH_(2)-CH=CH_(2)`

Answer

3

Explanation

`{:(CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(2)-NH_(2),),(" "darrCH_(3)I//AgOH,),(CH_(3)-CH_(2)-CH_(2)-CH=CH_(2),),(" "darrO_(3)//Zn//H_(2)O,),(CH_(3)-CH_(2)-CH_(2)-CHO+HCHO,):}`