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Let (+) tartaric acid has a specific rot...

Let `(+)` tartaric acid has a specific rotation of`+11.1`, Calculate the specific rotation of a mixture of `68%(+)` tartaric acid and `32%(-)` tartaric acid.

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The correct Answer is:
4

Enantiomeric excess `=(d-l)/(d+l)xx100=(68-32)/(68+32)xx100=36%`
`:.` Optical rotation of this mixture `=36%xx + (11.1^(0))=4`
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