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If a,b,c are in AP and A,B,C are in G.P....

If `a,b,c` are in AP and `A,B,C` are in G.P. (Common ratio `!=1`). Then which of the following is/are correct

A

`A/a,B/b,C/c` are in HP if common of GP is `c//a`

B

`a/A,b/B,c/C` are in HP if common ratio of GP is equal to common difference of AP

C

`(A^(2))/a,(B^(2))/b,(C^(2))/c` are in HP if common ratio of GP is `sqrt(c/a)`

D

`a/(A^(2)),b/(B^(2)),c/(C^(2))` are in HP if common ratio of GP is equal to square root of common difference of AP.

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

`A/a,B/b,C/c HP`
`=(2b)/B=a/A+c/C`
`implies2bB=aC+cA`
`impliesaB+cB=aC+cA`
`impliesa[B-C]=c[A-B]`
so `r=c/a`
`(A^(2))/a,(B^(2))/b,(C^(2))/c` are in `HPimpliesr^(2)=c/a`
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