An element undergoes s reaction as show -
`X+2e^(-)``rarrX^(2-)`, energy relesed `=30.87eV//"atom"`. If the energy released ,is used to dissociate 8 gms of `H_(2)` molecules,equally into `H^(+)` and `H^(ast)`,where `H^(ast)` is an exicted state of H atoms where the electron travels in orbit whose circumference equal to four times its de Broglie's wavelenght .
(a) Calculate the excited statue of H
(b) Determine the least amount of X that would be required .
Given : `IE of H = 13.6 eV//"atom"`, Bond energy of `H_(2) =4.526 eV//"molecule"`.

Options

A. 1
B. 2
C. 3
D. 4

Answer

B

Explanation

`2pir=4lamda,n=4`
Total energy required `+` Total energ released `=0`
`(2xx4.526"ev"xxN_(A))+(2xx13.6N_(A))+(2xx13.6xx(1-1/16)xxN_(1))-(30.87xx x xxN_(A))=0`
`x=2`