A Colorless solid `A` liberates a brown gas `B` on acidification, a colorless alkaline gas `(C)`on treatment with `NaOH` and a colorless non-reactive gas `D` on heating. If heating of the solid is continued, it completely disappears.
The compound `A` is

Options

A. `NH_(4)NO_(2)`
B. `PH_(4)NO_(3)`
C. `NH_(4)NO_(3)`
D. none of these

Answer

A

Explanation

Alkaline gas `C` with `NaOH` indicates that solid should be ammonium salt. Heating the salt, a colorless non-reaching gas `D` is formed. The gas `D` may be nitrogen. The compound may thus be `NH_(4)NO_(2)`. Reactions involved are as follows:
`underset (A) (NH_(4))NO_(2) overset(HCl)to NH_(4)Cl+HNO_(2)`
`2HNO_(2)toH_(2)O+2NO+[O]`
`2NO+2[O]tounderset(B Brown Gas)(2NO_(2))uarr`
`NH_(4)NO_(2)+NaOHrarrNaO_(2)+H_(2)O+underset(C)(NH_(3))uarr`
C
`underset (A) (NH_(4)NO_(2_((s)))) overset ("heat")to underset (D) (N_(2_(("gas"))))uarr+2H_(2)O_(("gas"))uarr`
`impliesN_(2)` is a diamagnetic Gas
`implies` Bond order of `N_(2)=3`