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In four atoms of same radius are placed ...

In four atoms of same radius are placed at the alternate corner of a cube touching each other, than the length of body diagonal of the cube is equal to `sqrt(x)xxR`, where `R` is the radius of atom. Find the value of `x`?

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The correct Answer is:
6
`[6]`

Face diagonal of cube `(AB)=2R`
Edge length of cube `(BE)=(2R)/(sqrt(2))`
Body diagonal of cube `(AD)=sqrt(3)xx(2R)/(sqrt(2))`
`=sqrt(6)xxR`
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